[y] and Qokeedy Cycles

Another essential difference between our two keywords, QOKEEDY and CHOLDAIIN, is that QOKEEDY is continuous, and cycles, whereas CHOLDAIIN does not. This is an important addenda to my previous post. In short:

QOKEEDY is continuous.

CHOLDAIIN is discontinuous.

This is the difference between [y] and [n]. While [n] terminates CHOLDAIIN, [y] – with its back tail – indicates: “AGAIN” and the cycle continues after the word break.

That is, QOKEEDY actually manifests as:

_[qokeedy]_[qokeedy]_[qokeedy]_

Whereas, CHOLDAIIN does not cycle like this. It is linear, not cyclic. The final [n] is final.

For this reason, there is a strong chance that [qo] will follow [y] in the next word. But a final [n] has no strong preference and does not imply the first glyph of the next word.

A final [y] implies a [q] after the word break. Why? Because this follows the pattern of the QOKEEDY paradigm, and it cycles, it is continuous.

This is the reason, too, that [y] can also appear as word-initial. In those cases, [y] has carried over from the end of the cycle to the beginning, and it replaces [qo]. Thus the cycle can be written as:

_[ykeedy]_[ykeedy]_[ykeedy]

Here the initial [y] supplies the circle, the [o] to the sequence. [y] = [o] – but only the [o] at the beginning of QOKEEDY. It is not that [y] = [o] in all cases; it can replace [o] (and [qo]) when it is marking the continuing cycle. 

[y] has two uses: it can appear at the start or the end of QOKEEDY in its cycles. It can be, as it were, carried over from the end to the new beginning. 

We can distinguish, therefore, between hard and soft word breaks.

QOKEEDY produces soft word breaks. The cycle continues.

CHOLDAIIN produces hard word breaks. No cycle. [n] never appears at the start of words after the word break in the way [y] does.

R.B.